A store owner has 84 more pears than chikoos. After he sold 75% of the pears and 40% of the chikoos, he is left with 21 less pears than chikoos. What fraction of the fruits left were chikoos?
| |
Pears |
Chikoos |
Comparing pears
and chikoos at first |
84 more |
|
| Before |
4x5 =
20 u |
+ 84 |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 63 |
- 2x4 =
- 8 u |
| After |
1x5 =
5 u |
+ 21 |
3x4 =
12 u |
Comparing pears
and chikoos in the end |
21 less |
|
75% =
75100 =
34 75% x 84 =
34 x 84 = 63
84 - 63 = 21
40% =
40100 =
25 The number of pears is 21 less than the number of chikoos in the end. So, if another 21 pears are added, the number of pears and chikoos in the end will be the same.
5 u + 21 + 21 = 12 u
5 u + 42 = 12 u
12 u - 5 u = 42
7 u = 42
1 u = 42 ÷ 7 = 6
Number of chikoos left
= 12 u
= 12 x 6
= 72
Total number of fruits left
= 5 u + 21 + 12 u
= 17 u + 21
= 17 x 6 + 21
= 102 + 21
= 123
Chikoos leftTotal fruits left =
72123 =
2441 Answer(s):
2441 
