A store owner has 56 more mangosteens than pears. After he sold 75% of the mangosteens and 35% of the pears, he is left with 26 less mangosteens than pears. What fraction of the fruits left were pears?
| |
Mangosteens |
Pears |
Comparing mangosteens
and pears at first |
56 more |
|
| Before |
4x5 =
20 u |
+ 56 |
20x1 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 42 |
- 7x1 =
- 7 u |
| After |
1x5 =
5 u |
+ 14 |
13x1 =
13 u |
Comparing mangosteens
and pears in the end |
26 less |
|
75% =
75100 =
34 75% x 56 =
34 x 56 = 42
56 - 42 = 14
35% =
35100 =
720 The number of mangosteens is 26 less than the number of pears in the end. So, if another 26 mangosteens are added, the number of mangosteens and pears in the end will be the same.
5 u + 14 + 26 = 13 u
5 u + 40 = 13 u
13 u - 5 u = 40
8 u = 40
1 u = 40 ÷ 8 = 5
Number of pears left
= 13 u
= 13 x 5
= 65
Total number of fruits left
= 5 u + 14 + 13 u
= 18 u + 14
= 18 x 5 + 14
= 90 + 14
= 104
Pears leftTotal fruits left =
65104 =
58 Answer(s):
58 
