A store owner has 45 less persimmons than starfruits. After he sold 80% of the persimmons and 30% of the starfruits, he is left with 51 less persimmons than starfruits. What fraction of the fruits left were persimmons?
|
Persimmons |
Starfruits |
Comparing persimmons and starfruits at first |
|
45 less |
Before |
5x2 = 10 u |
+ 45 |
10x1 = 10 u |
Change |
- 4x2 = - 8 u |
- 36 |
- 3x1 = - 3 u |
After |
1x2 = 2 u |
+ 9 |
7x1 = 7 u |
Comparing persimmons and starfruits in the end |
51 less |
|
80% =
80100 =
45 80% x 45 =
45 x 45 = 36
45 - 36 = 9
30% =
30100 =
310 The number of persimmons is 51 less than the number of starfruits in the end. So, if another 51 persimmons are added, the number of persimmons and starfruits in the end will be the same.
2 u + 9 + 51 = 7 u
2 u + 60 = 7 u
7 u - 2 u = 60
5 u = 60
1 u = 60 ÷ 5 = 12
Number of persimmons left
= 2 u + 9
= 2 x 12 + 9
= 24 + 9
= 33
Total number of fruits left
= 2 u + 9 + 7 u
= 9 u + 9
= 9 x 12 + 9
= 108 + 9
= 117
Persimmons leftTotal fruits left =
33117 =
1139 Answer(s):
1139