A store owner has 90 less kiwis than persimmons. After he sold 80% of the kiwis and 10% of the persimmons, he is left with 3 less kiwis than persimmons. What fraction of the fruits left were kiwis?
| |
Kiwis |
Persimmons |
Comparing kiwis
and persimmons at first |
|
90 less |
| Before |
5x2 =
10 u |
+ 90 |
10x1 =
10 u |
| Change |
- 4x2 =
- 8 u |
- 72 |
- 1x1 =
- 1 u |
| After |
1x2 =
2 u |
+ 18 |
9x1 =
9 u |
Comparing kiwis
and persimmons in the end |
3 less |
|
80% =
80100 =
45 80% x 90 =
45 x 90 = 72
90 - 72 = 18
10% =
10100 =
110 The number of kiwis is 3 less than the number of persimmons in the end. So, if another 3 kiwis are added, the number of kiwis and persimmons in the end will be the same.
2 u + 18 + 3 = 9 u
2 u + 21 = 9 u
9 u - 2 u = 21
7 u = 21
1 u = 21 ÷ 7 = 3
Number of kiwis left
= 2 u + 18
= 2 x 3 + 18
= 6 + 18
= 24
Total number of fruits left
= 2 u + 18 + 9 u
= 11 u + 18
= 11 x 3 + 18
= 33 + 18
= 51
Kiwis leftTotal fruits left =
2451 =
817 Answer(s):
817 
