A store owner has 60 more pomegranates than pears. After he sold 70% of the pomegranates and 35% of the pears, he is left with 66 more pears than pomegranates. What fraction of the fruits left were pears?
| |
Pomegranates |
Pears |
Comparing pomegranates
and pears at first |
60 more |
|
| Before |
10x2 =
20 u |
+ 60 |
20x1 =
20 u |
| Change |
- 7x2 =
- 14 u |
- 42 |
- 7x1 =
- 7 u |
| After |
3x2 =
6 u |
+ 18 |
13x1 =
13 u |
Comparing pomegranates
and pears in the end |
|
66 more |
70% =
70100 =
710 70% x 60 =
710 x 60 = 42
60 - 42 = 18
35% =
35100 =
720 The number of pears is 66 more than the number of pomegranates in the end. So, if another 66 pomegranates are added, the number of pomegranates and pears in the end will be the same.
6 u + 18 + 66 = 13 u
6 u + 84 = 13 u
13 u - 6 u = 84
7 u = 84
1 u = 84 ÷ 7 = 12
Number of pears left
= 13 u
= 13 x 12
= 156
Total number of fruits left
= 6 u + 18 + 13 u
= 19 u + 18
= 19 x 12 + 18
= 228 + 18
= 246
Pears leftTotal fruits left =
156246 =
2641 Answer(s):
2641 
