A store owner has 100 more kiwis than oranges. After he sold 70% of the kiwis and 35% of the oranges, he is left with 40 more oranges than kiwis. What fraction of the fruits left were oranges?
| |
Kiwis |
Oranges |
Comparing kiwis
and oranges at first |
100 more |
|
| Before |
10x2 =
20 u |
+ 100 |
20x1 =
20 u |
| Change |
- 7x2 =
- 14 u |
- 70 |
- 7x1 =
- 7 u |
| After |
3x2 =
6 u |
+ 30 |
13x1 =
13 u |
Comparing kiwis
and oranges in the end |
|
40 more |
70% =
70100 =
710 70% x 100 =
710 x 100 = 70
100 - 70 = 30
35% =
35100 =
720 The number of oranges is 40 more than the number of kiwis in the end. So, if another 40 kiwis are added, the number of kiwis and oranges in the end will be the same.
6 u + 30 + 40 = 13 u
6 u + 70 = 13 u
13 u - 6 u = 70
7 u = 70
1 u = 70 ÷ 7 = 10
Number of oranges left
= 13 u
= 13 x 10
= 130
Total number of fruits left
= 6 u + 30 + 13 u
= 19 u + 30
= 19 x 10 + 30
= 190 + 30
= 220
Oranges leftTotal fruits left =
130220 =
1322 Answer(s):
1322 
