A store owner has 100 less pomegranates than pears. After he sold 70% of the pomegranates and 35% of the pears, he is left with 26 less pomegranates than pears. What fraction of the fruits left were pomegranates?
|
Pomegranates |
Pears |
Comparing pomegranates and pears at first |
|
100 less |
Before |
10x2 = 20 u |
+ 100 |
20x1 = 20 u |
Change |
- 7x2 = - 14 u |
- 70 |
- 7x1 = - 7 u |
After |
3x2 = 6 u |
+ 30 |
13x1 = 13 u |
Comparing pomegranates and pears in the end |
26 less |
|
70% =
70100 =
710 70% x 100 =
710 x 100 = 70
100 - 70 = 30
35% =
35100 =
720 The number of pomegranates is 26 less than the number of pears in the end. So, if another 26 pomegranates are added, the number of pomegranates and pears in the end will be the same.
6 u + 30 + 26 = 13 u
6 u + 56 = 13 u
13 u - 6 u = 56
7 u = 56
1 u = 56 ÷ 7 = 8
Number of pomegranates left
= 6 u + 30
= 6 x 8 + 30
= 48 + 30
= 78
Total number of fruits left
= 6 u + 30 + 13 u
= 19 u + 30
= 19 x 8 + 30
= 152 + 30
= 182
Pomegranates leftTotal fruits left =
78182 =
37 Answer(s):
37