A store owner has 80 more oranges than pears. After he sold 80% of the oranges and 35% of the pears, he is left with 92 more pears than oranges. What fraction of the fruits left were pears?
| |
Oranges |
Pears |
Comparing oranges
and pears at first |
80 more |
|
| Before |
5x4 =
20 u |
+ 80 |
20x1 =
20 u |
| Change |
- 4x4 =
- 16 u |
- 64 |
- 7x1 =
- 7 u |
| After |
1x4 =
4 u |
+ 16 |
13x1 =
13 u |
Comparing oranges
and pears in the end |
|
92 more |
80% =
80100 =
45 80% x 80 =
45 x 80 = 64
80 - 64 = 16
35% =
35100 =
720 The number of pears is 92 more than the number of oranges in the end. So, if another 92 oranges are added, the number of oranges and pears in the end will be the same.
4 u + 16 + 92 = 13 u
4 u + 108 = 13 u
13 u - 4 u = 108
9 u = 108
1 u = 108 ÷ 9 = 12
Number of pears left
= 13 u
= 13 x 12
= 156
Total number of fruits left
= 4 u + 16 + 13 u
= 17 u + 16
= 17 x 12 + 16
= 204 + 16
= 220
Pears leftTotal fruits left =
156220 =
3955 Answer(s):
3955 
