A store owner has 20 more persimmons than apples. After he sold 75% of the persimmons and 40% of the apples, he is left with 51 less persimmons than apples. What fraction of the fruits left were apples?
| |
Persimmons |
Apples |
Comparing persimmons
and apples at first |
20 more |
|
| Before |
4x5 =
20 u |
+ 20 |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 15 |
- 2x4 =
- 8 u |
| After |
1x5 =
5 u |
+ 5 |
3x4 =
12 u |
Comparing persimmons
and apples in the end |
51 less |
|
75% =
75100 =
34 75% x 20 =
34 x 20 = 15
20 - 15 = 5
40% =
40100 =
25 The number of persimmons is 51 less than the number of apples in the end. So, if another 51 persimmons are added, the number of persimmons and apples in the end will be the same.
5 u + 5 + 51 = 12 u
5 u + 56 = 12 u
12 u - 5 u = 56
7 u = 56
1 u = 56 ÷ 7 = 8
Number of apples left
= 12 u
= 12 x 8
= 96
Total number of fruits left
= 5 u + 5 + 12 u
= 17 u + 5
= 17 x 8 + 5
= 136 + 5
= 141
Apples leftTotal fruits left =
96141 =
3247 Answer(s):
3247 
