A store owner has 100 more lemons than persimmons. After he sold 75% of the lemons and 10% of the persimmons, he is left with 27 more persimmons than lemons. What fraction of the fruits left were persimmons?
| |
Lemons |
Persimmons |
Comparing lemons
and persimmons at first |
100 more |
|
| Before |
4x5 =
20 u |
+ 100 |
10x2 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 75 |
- 1x2 =
- 2 u |
| After |
1x5 =
5 u |
+ 25 |
9x2 =
18 u |
Comparing lemons
and persimmons in the end |
|
27 more |
75% =
75100 =
34 75% x 100 =
34 x 100 = 75
100 - 75 = 25
10% =
10100 =
110 The number of persimmons is 27 more than the number of lemons in the end. So, if another 27 lemons are added, the number of lemons and persimmons in the end will be the same.
5 u + 25 + 27 = 18 u
5 u + 52 = 18 u
18 u - 5 u = 52
13 u = 52
1 u = 52 ÷ 13 = 4
Number of persimmons left
= 18 u
= 18 x 4
= 72
Total number of fruits left
= 5 u + 25 + 18 u
= 23 u + 25
= 23 x 4 + 25
= 92 + 25
= 117
Persimmons leftTotal fruits left =
72117 =
813 Answer(s):
813 
