A store owner has 40 more chikoos than pears. After he sold 75% of the chikoos and 10% of the pears, he is left with 94 less chikoos than pears. What fraction of the fruits left were pears?
| |
Chikoos |
Pears |
Comparing chikoos
and pears at first |
40 more |
|
| Before |
4x5 =
20 u |
+ 40 |
10x2 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 30 |
- 1x2 =
- 2 u |
| After |
1x5 =
5 u |
+ 10 |
9x2 =
18 u |
Comparing chikoos
and pears in the end |
94 less |
|
75% =
75100 =
34 75% x 40 =
34 x 40 = 30
40 - 30 = 10
10% =
10100 =
110 The number of chikoos is 94 less than the number of pears in the end. So, if another 94 chikoos are added, the number of chikoos and pears in the end will be the same.
5 u + 10 + 94 = 18 u
5 u + 104 = 18 u
18 u - 5 u = 104
13 u = 104
1 u = 104 ÷ 13 = 8
Number of pears left
= 18 u
= 18 x 8
= 144
Total number of fruits left
= 5 u + 10 + 18 u
= 23 u + 10
= 23 x 8 + 10
= 184 + 10
= 194
Pears leftTotal fruits left =
144194 =
7297 Answer(s):
7297 
