A store owner has 60 more apples than persimmons. After he sold 70% of the apples and 40% of the persimmons, he is left with 6 more persimmons than apples. What fraction of the fruits left were persimmons?
| |
Apples |
Persimmons |
Comparing apples
and persimmons at first |
60 more |
|
| Before |
10x1 =
10 u |
+ 60 |
5x2 =
10 u |
| Change |
- 7x1 =
- 7 u |
- 42 |
- 2x2 =
- 4 u |
| After |
3x1 =
3 u |
+ 18 |
3x2 =
6 u |
Comparing apples
and persimmons in the end |
|
6 more |
70% =
70100 =
710 70% x 60 =
710 x 60 = 42
60 - 42 = 18
40% =
40100 =
25 The number of persimmons is 6 more than the number of apples in the end. So, if another 6 apples are added, the number of apples and persimmons in the end will be the same.
3 u + 18 + 6 = 6 u
3 u + 24 = 6 u
6 u - 3 u = 24
3 u = 24
1 u = 24 ÷ 3 = 8
Number of persimmons left
= 6 u
= 6 x 8
= 48
Total number of fruits left
= 3 u + 18 + 6 u
= 9 u + 18
= 9 x 8 + 18
= 72 + 18
= 90
Persimmons leftTotal fruits left =
4890 =
815 Answer(s):
815 
