A store owner has 100 more oranges than lemons. After he sold 70% of the oranges and 20% of the lemons, he is left with 20 more lemons than oranges. What fraction of the fruits left were lemons?
|
Oranges |
Lemons |
Comparing oranges and lemons at first |
100 more |
|
Before |
10x1 = 10 u |
+ 100 |
5x2 = 10 u |
Change |
- 7x1 = - 7 u |
- 70 |
- 1x2 = - 2 u |
After |
3x1 = 3 u |
+ 30 |
4x2 = 8 u |
Comparing oranges and lemons in the end |
|
20 more |
70% =
70100 =
710 70% x 100 =
710 x 100 = 70
100 - 70 = 30
20% =
20100 =
15 The number of lemons is 20 more than the number of oranges in the end. So, if another 20 oranges are added, the number of oranges and lemons in the end will be the same.
3 u + 30 + 20 = 8 u
3 u + 50 = 8 u
8 u - 3 u = 50
5 u = 50
1 u = 50 ÷ 5 = 10
Number of lemons left
= 8 u
= 8 x 10
= 80
Total number of fruits left
= 3 u + 30 + 8 u
= 11 u + 30
= 11 x 10 + 30
= 110 + 30
= 140
Lemons leftTotal fruits left =
80140 =
47 Answer(s):
47