A store owner has 40 more oranges than chikoos. After he sold 60% of the oranges and 35% of the chikoos, he is left with 44 more chikoos than oranges. What fraction of the fruits left were chikoos?
| |
Oranges |
Chikoos |
Comparing oranges
and chikoos at first |
40 more |
|
| Before |
5x4 =
20 u |
+ 40 |
20x1 =
20 u |
| Change |
- 3x4 =
- 12 u |
- 24 |
- 7x1 =
- 7 u |
| After |
2x4 =
8 u |
+ 16 |
13x1 =
13 u |
Comparing oranges
and chikoos in the end |
|
44 more |
60% =
60100 =
35 60% x 40 =
35 x 40 = 24
40 - 24 = 16
35% =
35100 =
720 The number of chikoos is 44 more than the number of oranges in the end. So, if another 44 oranges are added, the number of oranges and chikoos in the end will be the same.
8 u + 16 + 44 = 13 u
8 u + 60 = 13 u
13 u - 8 u = 60
5 u = 60
1 u = 60 ÷ 5 = 12
Number of chikoos left
= 13 u
= 13 x 12
= 156
Total number of fruits left
= 8 u + 16 + 13 u
= 21 u + 16
= 21 x 12 + 16
= 252 + 16
= 268
Chikoos leftTotal fruits left =
156268 =
3967 Answer(s):
3967 
