A store owner has 72 less apples than chikoos. After he sold 75% of the apples and 10% of the chikoos, he is left with 21 less apples than chikoos. What fraction of the fruits left were apples?
| |
Apples |
Chikoos |
Comparing apples
and chikoos at first |
|
72 less |
| Before |
4x5 =
20 u |
+ 72 |
10x2 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 54 |
- 1x2 =
- 2 u |
| After |
1x5 =
5 u |
+ 18 |
9x2 =
18 u |
Comparing apples
and chikoos in the end |
21 less |
|
75% =
75100 =
34 75% x 72 =
34 x 72 = 54
72 - 54 = 18
10% =
10100 =
110 The number of apples is 21 less than the number of chikoos in the end. So, if another 21 apples are added, the number of apples and chikoos in the end will be the same.
5 u + 18 + 21 = 18 u
5 u + 39 = 18 u
18 u - 5 u = 39
13 u = 39
1 u = 39 ÷ 13 = 3
Number of apples left
= 5 u + 18
= 5 x 3 + 18
= 15 + 18
= 33
Total number of fruits left
= 5 u + 18 + 18 u
= 23 u + 18
= 23 x 3 + 18
= 69 + 18
= 87
Apples leftTotal fruits left =
3387 =
1129 Answer(s):
1129 
