A store owner has 60 less starfruits than chikoos. After he sold 90% of the starfruits and 40% of the chikoos, he is left with 44 less starfruits than chikoos. What fraction of the fruits left were starfruits?
| |
Starfruits |
Chikoos |
Comparing starfruits
and chikoos at first |
|
60 less |
| Before |
10x1 =
10 u |
+ 60 |
5x2 =
10 u |
| Change |
- 9x1 =
- 9 u |
- 54 |
- 2x2 =
- 4 u |
| After |
1x1 =
1 u |
+ 6 |
3x2 =
6 u |
Comparing starfruits
and chikoos in the end |
44 less |
|
90% =
90100 =
910 90% x 60 =
910 x 60 = 54
60 - 54 = 6
40% =
40100 =
25 The number of starfruits is 44 less than the number of chikoos in the end. So, if another 44 starfruits are added, the number of starfruits and chikoos in the end will be the same.
1 u + 6 + 44 = 6 u
1 u + 50 = 6 u
6 u - 1 u = 50
5 u = 50
1 u = 50 ÷ 5 = 10
Number of starfruits left
= 1 u + 6
= 1 x 10 + 6
= 10 + 6
= 16
Total number of fruits left
= 1 u + 6 + 6 u
= 7 u + 6
= 7 x 10 + 6
= 70 + 6
= 76
Starfruits leftTotal fruits left =
1676 =
419 Answer(s):
419 
