A store owner has 30 less apples than persimmons. After he sold 90% of the apples and 20% of the persimmons, he is left with 74 less apples than persimmons. What fraction of the fruits left were apples?
| |
Apples |
Persimmons |
Comparing apples
and persimmons at first |
|
30 less |
| Before |
10x1 =
10 u |
+ 30 |
5x2 =
10 u |
| Change |
- 9x1 =
- 9 u |
- 27 |
- 1x2 =
- 2 u |
| After |
1x1 =
1 u |
+ 3 |
4x2 =
8 u |
Comparing apples
and persimmons in the end |
74 less |
|
90% =
90100 =
910 90% x 30 =
910 x 30 = 27
30 - 27 = 3
20% =
20100 =
15 The number of apples is 74 less than the number of persimmons in the end. So, if another 74 apples are added, the number of apples and persimmons in the end will be the same.
1 u + 3 + 74 = 8 u
1 u + 77 = 8 u
8 u - 1 u = 77
7 u = 77
1 u = 77 ÷ 7 = 11
Number of apples left
= 1 u + 3
= 1 x 11 + 3
= 11 + 3
= 14
Total number of fruits left
= 1 u + 3 + 8 u
= 9 u + 3
= 9 x 11 + 3
= 99 + 3
= 102
Apples leftTotal fruits left =
14102 =
751 Answer(s):
751 
