A store owner has 60 less lemons than starfruits. After he sold 90% of the lemons and 40% of the starfruits, he is left with 54 less lemons than starfruits. What fraction of the fruits left were lemons?
| |
Lemons |
Starfruits |
Comparing lemons
and starfruits at first |
|
60 less |
| Before |
10x1 =
10 u |
+ 60 |
5x2 =
10 u |
| Change |
- 9x1 =
- 9 u |
- 54 |
- 2x2 =
- 4 u |
| After |
1x1 =
1 u |
+ 6 |
3x2 =
6 u |
Comparing lemons
and starfruits in the end |
54 less |
|
90% =
90100 =
910 90% x 60 =
910 x 60 = 54
60 - 54 = 6
40% =
40100 =
25 The number of lemons is 54 less than the number of starfruits in the end. So, if another 54 lemons are added, the number of lemons and starfruits in the end will be the same.
1 u + 6 + 54 = 6 u
1 u + 60 = 6 u
6 u - 1 u = 60
5 u = 60
1 u = 60 ÷ 5 = 12
Number of lemons left
= 1 u + 6
= 1 x 12 + 6
= 12 + 6
= 18
Total number of fruits left
= 1 u + 6 + 6 u
= 7 u + 6
= 7 x 12 + 6
= 84 + 6
= 90
Lemons leftTotal fruits left =
1890 =
15 Answer(s):
15 
