A store owner has 20 less oranges than chikoos. After he sold 90% of the oranges and 35% of the chikoos, he is left with 64 less oranges than chikoos. What fraction of the fruits left were oranges?
| |
Oranges |
Chikoos |
Comparing oranges
and chikoos at first |
|
20 less |
| Before |
10x2 =
20 u |
+ 20 |
20x1 =
20 u |
| Change |
- 9x2 =
- 18 u |
- 18 |
- 7x1 =
- 7 u |
| After |
1x2 =
2 u |
+ 2 |
13x1 =
13 u |
Comparing oranges
and chikoos in the end |
64 less |
|
90% =
90100 =
910 90% x 20 =
910 x 20 = 18
20 - 18 = 2
35% =
35100 =
720 The number of oranges is 64 less than the number of chikoos in the end. So, if another 64 oranges are added, the number of oranges and chikoos in the end will be the same.
2 u + 2 + 64 = 13 u
2 u + 66 = 13 u
13 u - 2 u = 66
11 u = 66
1 u = 66 ÷ 11 = 6
Number of oranges left
= 2 u + 2
= 2 x 6 + 2
= 12 + 2
= 14
Total number of fruits left
= 2 u + 2 + 13 u
= 15 u + 2
= 15 x 6 + 2
= 90 + 2
= 92
Oranges leftTotal fruits left =
1492 =
746 Answer(s):
746 
