A store owner has 100 more lemons than kiwis. After he sold 80% of the lemons and 30% of the kiwis, he is left with 10 less lemons than kiwis. What fraction of the fruits left were kiwis?
| |
Lemons |
Kiwis |
Comparing lemons
and kiwis at first |
100 more |
|
| Before |
5x2 =
10 u |
+ 100 |
10x1 =
10 u |
| Change |
- 4x2 =
- 8 u |
- 80 |
- 3x1 =
- 3 u |
| After |
1x2 =
2 u |
+ 20 |
7x1 =
7 u |
Comparing lemons
and kiwis in the end |
10 less |
|
80% =
80100 =
45 80% x 100 =
45 x 100 = 80
100 - 80 = 20
30% =
30100 =
310 The number of lemons is 10 less than the number of kiwis in the end. So, if another 10 lemons are added, the number of lemons and kiwis in the end will be the same.
2 u + 20 + 10 = 7 u
2 u + 30 = 7 u
7 u - 2 u = 30
5 u = 30
1 u = 30 ÷ 5 = 6
Number of kiwis left
= 7 u
= 7 x 6
= 42
Total number of fruits left
= 2 u + 20 + 7 u
= 9 u + 20
= 9 x 6 + 20
= 54 + 20
= 74
Kiwis leftTotal fruits left =
4274 =
2137 Answer(s):
2137 
