A store owner has 80 more apples than kiwis. After he sold 75% of the apples and 35% of the kiwis, he is left with 44 more kiwis than apples. What fraction of the fruits left were kiwis?
| |
Apples |
Kiwis |
Comparing apples
and kiwis at first |
80 more |
|
| Before |
4x5 =
20 u |
+ 80 |
20x1 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 60 |
- 7x1 =
- 7 u |
| After |
1x5 =
5 u |
+ 20 |
13x1 =
13 u |
Comparing apples
and kiwis in the end |
|
44 more |
75% =
75100 =
34 75% x 80 =
34 x 80 = 60
80 - 60 = 20
35% =
35100 =
720 The number of kiwis is 44 more than the number of apples in the end. So, if another 44 apples are added, the number of apples and kiwis in the end will be the same.
5 u + 20 + 44 = 13 u
5 u + 64 = 13 u
13 u - 5 u = 64
8 u = 64
1 u = 64 ÷ 8 = 8
Number of kiwis left
= 13 u
= 13 x 8
= 104
Total number of fruits left
= 5 u + 20 + 13 u
= 18 u + 20
= 18 x 8 + 20
= 144 + 20
= 164
Kiwis leftTotal fruits left =
104164 =
2641 Answer(s):
2641 
