A store owner has 52 more apples than chikoos. After he sold 75% of the apples and 10% of the chikoos, he is left with 130 more chikoos than apples. What fraction of the fruits left were chikoos?
| |
Apples |
Chikoos |
Comparing apples
and chikoos at first |
52 more |
|
| Before |
4x5 =
20 u |
+ 52 |
10x2 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 39 |
- 1x2 =
- 2 u |
| After |
1x5 =
5 u |
+ 13 |
9x2 =
18 u |
Comparing apples
and chikoos in the end |
|
130 more |
75% =
75100 =
34 75% x 52 =
34 x 52 = 39
52 - 39 = 13
10% =
10100 =
110 The number of chikoos is 130 more than the number of apples in the end. So, if another 130 apples are added, the number of apples and chikoos in the end will be the same.
5 u + 13 + 130 = 18 u
5 u + 143 = 18 u
18 u - 5 u = 143
13 u = 143
1 u = 143 ÷ 13 = 11
Number of chikoos left
= 18 u
= 18 x 11
= 198
Total number of fruits left
= 5 u + 13 + 18 u
= 23 u + 13
= 23 x 11 + 13
= 253 + 13
= 266
Chikoos leftTotal fruits left =
198266 =
99133 Answer(s):
99133 
