A store owner has 100 more apples than mangoes. After he sold 90% of the apples and 40% of the mangoes, he is left with 20 more mangoes than apples. What fraction of the fruits left were mangoes?
| |
Apples |
Mangoes |
Comparing apples
and mangoes at first |
100 more |
|
| Before |
10x1 =
10 u |
+ 100 |
5x2 =
10 u |
| Change |
- 9x1 =
- 9 u |
- 90 |
- 2x2 =
- 4 u |
| After |
1x1 =
1 u |
+ 10 |
3x2 =
6 u |
Comparing apples
and mangoes in the end |
|
20 more |
90% =
90100 =
910 90% x 100 =
910 x 100 = 90
100 - 90 = 10
40% =
40100 =
25 The number of mangoes is 20 more than the number of apples in the end. So, if another 20 apples are added, the number of apples and mangoes in the end will be the same.
1 u + 10 + 20 = 6 u
1 u + 30 = 6 u
6 u - 1 u = 30
5 u = 30
1 u = 30 ÷ 5 = 6
Number of mangoes left
= 6 u
= 6 x 6
= 36
Total number of fruits left
= 1 u + 10 + 6 u
= 7 u + 10
= 7 x 6 + 10
= 42 + 10
= 52
Mangoes leftTotal fruits left =
3652 =
913 Answer(s):
913 
