A store owner has 80 less pears than starfruits. After he sold 70% of the pears and 40% of the starfruits, he is left with 6 less pears than starfruits. What fraction of the fruits left were pears?
| |
Pears |
Starfruits |
Comparing pears
and starfruits at first |
|
80 less |
| Before |
10x1 =
10 u |
+ 80 |
5x2 =
10 u |
| Change |
- 7x1 =
- 7 u |
- 56 |
- 2x2 =
- 4 u |
| After |
3x1 =
3 u |
+ 24 |
3x2 =
6 u |
Comparing pears
and starfruits in the end |
6 less |
|
70% =
70100 =
710 70% x 80 =
710 x 80 = 56
80 - 56 = 24
40% =
40100 =
25 The number of pears is 6 less than the number of starfruits in the end. So, if another 6 pears are added, the number of pears and starfruits in the end will be the same.
3 u + 24 + 6 = 6 u
3 u + 30 = 6 u
6 u - 3 u = 30
3 u = 30
1 u = 30 ÷ 3 = 10
Number of pears left
= 3 u + 24
= 3 x 10 + 24
= 30 + 24
= 54
Total number of fruits left
= 3 u + 24 + 6 u
= 9 u + 24
= 9 x 10 + 24
= 90 + 24
= 114
Pears leftTotal fruits left =
54114 =
919 Answer(s):
919 
