A store owner has 64 less pears than oranges. After he sold 75% of the pears and 20% of the oranges, he is left with 94 less pears than oranges. What fraction of the fruits left were pears?
| |
Pears |
Oranges |
Comparing pears
and oranges at first |
|
64 less |
| Before |
4x5 =
20 u |
+ 64 |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 48 |
- 1x4 =
- 4 u |
| After |
1x5 =
5 u |
+ 16 |
4x4 =
16 u |
Comparing pears
and oranges in the end |
94 less |
|
75% =
75100 =
34 75% x 64 =
34 x 64 = 48
64 - 48 = 16
20% =
20100 =
15 The number of pears is 94 less than the number of oranges in the end. So, if another 94 pears are added, the number of pears and oranges in the end will be the same.
5 u + 16 + 94 = 16 u
5 u + 110 = 16 u
16 u - 5 u = 110
11 u = 110
1 u = 110 ÷ 11 = 10
Number of pears left
= 5 u + 16
= 5 x 10 + 16
= 50 + 16
= 66
Total number of fruits left
= 5 u + 16 + 16 u
= 21 u + 16
= 21 x 10 + 16
= 210 + 16
= 226
Pears leftTotal fruits left =
66226 =
33113 Answer(s):
33113 
