A store owner has 90 more apples than persimmons. After he sold 90% of the apples and 20% of the persimmons, he is left with 33 more persimmons than apples. What fraction of the fruits left were persimmons?
| |
Apples |
Persimmons |
Comparing apples
and persimmons at first |
90 more |
|
| Before |
10x1 =
10 u |
+ 90 |
5x2 =
10 u |
| Change |
- 9x1 =
- 9 u |
- 81 |
- 1x2 =
- 2 u |
| After |
1x1 =
1 u |
+ 9 |
4x2 =
8 u |
Comparing apples
and persimmons in the end |
|
33 more |
90% =
90100 =
910 90% x 90 =
910 x 90 = 81
90 - 81 = 9
20% =
20100 =
15 The number of persimmons is 33 more than the number of apples in the end. So, if another 33 apples are added, the number of apples and persimmons in the end will be the same.
1 u + 9 + 33 = 8 u
1 u + 42 = 8 u
8 u - 1 u = 42
7 u = 42
1 u = 42 ÷ 7 = 6
Number of persimmons left
= 8 u
= 8 x 6
= 48
Total number of fruits left
= 1 u + 9 + 8 u
= 9 u + 9
= 9 x 6 + 9
= 54 + 9
= 63
Persimmons leftTotal fruits left =
4863 =
1621 Answer(s):
1621 
