A store owner has 56 more lemons than oranges. After he sold 75% of the lemons and 10% of the oranges, he is left with 77 more oranges than lemons. What fraction of the fruits left were oranges?
| |
Lemons |
Oranges |
Comparing lemons
and oranges at first |
56 more |
|
| Before |
4x5 =
20 u |
+ 56 |
10x2 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 42 |
- 1x2 =
- 2 u |
| After |
1x5 =
5 u |
+ 14 |
9x2 =
18 u |
Comparing lemons
and oranges in the end |
|
77 more |
75% =
75100 =
34 75% x 56 =
34 x 56 = 42
56 - 42 = 14
10% =
10100 =
110 The number of oranges is 77 more than the number of lemons in the end. So, if another 77 lemons are added, the number of lemons and oranges in the end will be the same.
5 u + 14 + 77 = 18 u
5 u + 91 = 18 u
18 u - 5 u = 91
13 u = 91
1 u = 91 ÷ 13 = 7
Number of oranges left
= 18 u
= 18 x 7
= 126
Total number of fruits left
= 5 u + 14 + 18 u
= 23 u + 14
= 23 x 7 + 14
= 161 + 14
= 175
Oranges leftTotal fruits left =
126175 =
1825 Answer(s):
1825 
