A store owner has 28 more oranges than pears. After he sold 75% of the oranges and 30% of the pears, he is left with 38 less oranges than pears. What fraction of the fruits left were pears?
| |
Oranges |
Pears |
Comparing oranges
and pears at first |
28 more |
|
| Before |
4x5 =
20 u |
+ 28 |
10x2 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 21 |
- 3x2 =
- 6 u |
| After |
1x5 =
5 u |
+ 7 |
7x2 =
14 u |
Comparing oranges
and pears in the end |
38 less |
|
75% =
75100 =
34 75% x 28 =
34 x 28 = 21
28 - 21 = 7
30% =
30100 =
310 The number of oranges is 38 less than the number of pears in the end. So, if another 38 oranges are added, the number of oranges and pears in the end will be the same.
5 u + 7 + 38 = 14 u
5 u + 45 = 14 u
14 u - 5 u = 45
9 u = 45
1 u = 45 ÷ 9 = 5
Number of pears left
= 14 u
= 14 x 5
= 70
Total number of fruits left
= 5 u + 7 + 14 u
= 19 u + 7
= 19 x 5 + 7
= 95 + 7
= 102
Pears leftTotal fruits left =
70102 =
3551 Answer(s):
3551 
