A store owner has 40 less lemons than chikoos. After he sold 90% of the lemons and 40% of the chikoos, he is left with 46 less lemons than chikoos. What fraction of the fruits left were lemons?
| |
Lemons |
Chikoos |
Comparing lemons
and chikoos at first |
|
40 less |
| Before |
10x1 =
10 u |
+ 40 |
5x2 =
10 u |
| Change |
- 9x1 =
- 9 u |
- 36 |
- 2x2 =
- 4 u |
| After |
1x1 =
1 u |
+ 4 |
3x2 =
6 u |
Comparing lemons
and chikoos in the end |
46 less |
|
90% =
90100 =
910 90% x 40 =
910 x 40 = 36
40 - 36 = 4
40% =
40100 =
25 The number of lemons is 46 less than the number of chikoos in the end. So, if another 46 lemons are added, the number of lemons and chikoos in the end will be the same.
1 u + 4 + 46 = 6 u
1 u + 50 = 6 u
6 u - 1 u = 50
5 u = 50
1 u = 50 ÷ 5 = 10
Number of lemons left
= 1 u + 4
= 1 x 10 + 4
= 10 + 4
= 14
Total number of fruits left
= 1 u + 4 + 6 u
= 7 u + 4
= 7 x 10 + 4
= 70 + 4
= 74
Lemons leftTotal fruits left =
1474 =
737 Answer(s):
737 
