A store owner has 35 less chikoos than persimmons. After he sold 80% of the chikoos and 35% of the persimmons, he is left with 56 less chikoos than persimmons. What fraction of the fruits left were chikoos?
| |
Chikoos |
Persimmons |
Comparing chikoos
and persimmons at first |
|
35 less |
| Before |
5x4 =
20 u |
+ 35 |
20x1 =
20 u |
| Change |
- 4x4 =
- 16 u |
- 28 |
- 7x1 =
- 7 u |
| After |
1x4 =
4 u |
+ 7 |
13x1 =
13 u |
Comparing chikoos
and persimmons in the end |
56 less |
|
80% =
80100 =
45 80% x 35 =
45 x 35 = 28
35 - 28 = 7
35% =
35100 =
720 The number of chikoos is 56 less than the number of persimmons in the end. So, if another 56 chikoos are added, the number of chikoos and persimmons in the end will be the same.
4 u + 7 + 56 = 13 u
4 u + 63 = 13 u
13 u - 4 u = 63
9 u = 63
1 u = 63 ÷ 9 = 7
Number of chikoos left
= 4 u + 7
= 4 x 7 + 7
= 28 + 7
= 35
Total number of fruits left
= 4 u + 7 + 13 u
= 17 u + 7
= 17 x 7 + 7
= 119 + 7
= 126
Chikoos leftTotal fruits left =
35126 =
518 Answer(s):
518 
