A store owner has 80 more starfruits than pears. After he sold 75% of the starfruits and 30% of the pears, he is left with 7 less starfruits than pears. What fraction of the fruits left were pears?
| |
Starfruits |
Pears |
Comparing starfruits
and pears at first |
80 more |
|
| Before |
4x5 =
20 u |
+ 80 |
10x2 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 60 |
- 3x2 =
- 6 u |
| After |
1x5 =
5 u |
+ 20 |
7x2 =
14 u |
Comparing starfruits
and pears in the end |
7 less |
|
75% =
75100 =
34 75% x 80 =
34 x 80 = 60
80 - 60 = 20
30% =
30100 =
310 The number of starfruits is 7 less than the number of pears in the end. So, if another 7 starfruits are added, the number of starfruits and pears in the end will be the same.
5 u + 20 + 7 = 14 u
5 u + 27 = 14 u
14 u - 5 u = 27
9 u = 27
1 u = 27 ÷ 9 = 3
Number of pears left
= 14 u
= 14 x 3
= 42
Total number of fruits left
= 5 u + 20 + 14 u
= 19 u + 20
= 19 x 3 + 20
= 57 + 20
= 77
Pears leftTotal fruits left =
4277 =
611 Answer(s):
611 
