A store owner has 80 less kiwis than persimmons. After he sold 80% of the kiwis and 30% of the persimmons, he is left with 24 less kiwis than persimmons. What fraction of the fruits left were kiwis?
| |
Kiwis |
Persimmons |
Comparing kiwis
and persimmons at first |
|
80 less |
| Before |
5x2 =
10 u |
+ 80 |
10x1 =
10 u |
| Change |
- 4x2 =
- 8 u |
- 64 |
- 3x1 =
- 3 u |
| After |
1x2 =
2 u |
+ 16 |
7x1 =
7 u |
Comparing kiwis
and persimmons in the end |
24 less |
|
80% =
80100 =
45 80% x 80 =
45 x 80 = 64
80 - 64 = 16
30% =
30100 =
310 The number of kiwis is 24 less than the number of persimmons in the end. So, if another 24 kiwis are added, the number of kiwis and persimmons in the end will be the same.
2 u + 16 + 24 = 7 u
2 u + 40 = 7 u
7 u - 2 u = 40
5 u = 40
1 u = 40 ÷ 5 = 8
Number of kiwis left
= 2 u + 16
= 2 x 8 + 16
= 16 + 16
= 32
Total number of fruits left
= 2 u + 16 + 7 u
= 9 u + 16
= 9 x 8 + 16
= 72 + 16
= 88
Kiwis leftTotal fruits left =
3288 =
411 Answer(s):
411 
