A store owner has 56 more apples than persimmons. After he sold 75% of the apples and 30% of the persimmons, he is left with 76 more persimmons than apples. What fraction of the fruits left were persimmons?
| |
Apples |
Persimmons |
Comparing apples
and persimmons at first |
56 more |
|
| Before |
4x5 =
20 u |
+ 56 |
10x2 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 42 |
- 3x2 =
- 6 u |
| After |
1x5 =
5 u |
+ 14 |
7x2 =
14 u |
Comparing apples
and persimmons in the end |
|
76 more |
75% =
75100 =
34 75% x 56 =
34 x 56 = 42
56 - 42 = 14
30% =
30100 =
310 The number of persimmons is 76 more than the number of apples in the end. So, if another 76 apples are added, the number of apples and persimmons in the end will be the same.
5 u + 14 + 76 = 14 u
5 u + 90 = 14 u
14 u - 5 u = 90
9 u = 90
1 u = 90 ÷ 9 = 10
Number of persimmons left
= 14 u
= 14 x 10
= 140
Total number of fruits left
= 5 u + 14 + 14 u
= 19 u + 14
= 19 x 10 + 14
= 190 + 14
= 204
Persimmons leftTotal fruits left =
140204 =
3551 Answer(s):
3551 
