A store owner has 76 more lemons than apples. After he sold 75% of the lemons and 10% of the apples, he is left with 72 more apples than lemons. What fraction of the fruits left were apples?
| |
Lemons |
Apples |
Comparing lemons
and apples at first |
76 more |
|
| Before |
4x5 =
20 u |
+ 76 |
10x2 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 57 |
- 1x2 =
- 2 u |
| After |
1x5 =
5 u |
+ 19 |
9x2 =
18 u |
Comparing lemons
and apples in the end |
|
72 more |
75% =
75100 =
34 75% x 76 =
34 x 76 = 57
76 - 57 = 19
10% =
10100 =
110 The number of apples is 72 more than the number of lemons in the end. So, if another 72 lemons are added, the number of lemons and apples in the end will be the same.
5 u + 19 + 72 = 18 u
5 u + 91 = 18 u
18 u - 5 u = 91
13 u = 91
1 u = 91 ÷ 13 = 7
Number of apples left
= 18 u
= 18 x 7
= 126
Total number of fruits left
= 5 u + 19 + 18 u
= 23 u + 19
= 23 x 7 + 19
= 161 + 19
= 180
Apples leftTotal fruits left =
126180 =
710 Answer(s):
710 
