Container E and Container F were filled completely with pepper. The total mass of ¹₆ of the pepper in Container F and ¹₁₁ of the pepper in Container E was 580 g. If ²₁₁ of the pepper in Container E was poured out, the total mass of the pepper in both containers became 4.02 kg. How much pepper was in

1. Container E in grams?
2. Container F in grams?

(a)
Let the mass of the pepper in Container F be F.
Let the mass of the pepper in Container E be E.

¹₆ F + ¹₁₁ E = 580 --- (1)

Fraction of the pepper left in Container E after ²₁₁ of it was poured out
= 1 - ²₁₁
= ⁹₁₁

1 kg = 1000 g
4.02 kg = 4020 g

1 F + ⁹₁₁ E = 4020
1 F = 4020 - ⁹₁₁ E --- (2)

Make F the same.

(1)_x6
⁶₆ F + ⁶₁₁ E = 3480
1 F + ⁶₁₁ E = 3480
1 F = 3480 - ⁶₁₁ E --- (3)

(3) = (2) 
3480 - ⁶₁₁ E = 4020 - ⁹₁₁ X
⁹₁₁ E - ⁶₁₁ E = 4020 - 3480
³₁₁ E = 540
¹₁₁ E = 540 ÷ 3 = 180

¹¹₁₁ E = 11 x 180 = 1980

1 E = 1980

Mass of Container E = 1980 g

(b)
From (1)
¹₆ F + 180 = 580
¹₆ F = 580 - 180 = 400

⁶₆ F = 6 x 400 = 2400

1 F = 2400

Mass of Container F = 2400 g

Answer(s): (a) 1980 g; (b) 2400 g