Three types of chicken powder, R, S and T come in containers of 120 g, 200 g and 320 g respectively. Containers of R, S and T are mixed together in the ratio 1 : 2 : 5 to obtain 23.32 kg of an assortment of chicken powder.
- How many containers of R and S are used altogether?
- Find the difference between the combined weight of all the chicken powder in containers S and containers T as compared to the chicken powder in containers R. Express the weight in kilograms.
|
R |
S |
T |
Number |
1 u |
2 u |
5 u |
Value |
120 |
200 |
320 |
Total value |
120 u |
400 u |
1600 u |
(a)
Total mass of chicken powder
= 120 u + 400 u + 1600 u
= 2120 u
2120 u = 23320
1 u = 23320 ÷ 2120 = 11
Total number of containers of R and S used
= 1 u + 2 u
= 3 u
= 3 x 11
= 33
(b)
Combined weight of all the chicken powder in containers S and containers T
= 400 u + 1600 u
= 2000 u
Difference between the combined weight of all the chicken powder in containers S and containers T as compared to the chicken powder in containers R
= 2000 u - 120 u
= 1880 u
= 1880 x 11
= 20680 g
= 20.68 kg
Answer(s): (a) 33; (b) 20.68 kg