Container R and Container S had 48 kg of flour and 128.7 kg of flour respectively. If 2 kg of flour and 7.7 kg of flour are added into Container R and Container S every day, how many days later will the flour in Container R be one-third as much as the flour in Container S?
| |
Make p the same
(1)x3 = (3) |
Container R
(1) |
Container S
(2) |
| Before |
144 |
48 |
128.7 |
| Change |
+ 6 u |
+ 2 u |
+ 7.7 u |
| After |
3 p |
1 p |
3 p |
48 + 2 u = 1 p --- (1)
128.7 + 7.7 u =
3 p --- (2)
Make p the same.
(1)
x3 = (3)
144 + 6 u =
3 p --- (3)
(2) = (3)
128.7 + 7.7 u = 144 + 6 u
7.7 u - 6 u = 144 - 128.7
1.7 u = 15.3
1 u = 15.3 ÷ 1.7 = 9
Time taken for the flour in Container R to be one-third as much as the flour in Container S = 9
Answer(s): 9
