Cindy has 30% as many erasers as Joelle. Joelle has 140% as many erasers as Linda. If Joelle gives 120 erasers to Linda, both will then have an equal number of erasers. Find the average number of erasers the three of them have.
Cindy |
Joelle |
Linda |
3x7 |
10x7 |
|
|
7x10 |
5x10 |
21 u |
70 u |
50 u |
30% =
30100 =
310140% =
140100=
75The number of erasers that Cindy has is repeated. Make the number of erasers that Cindy has the same. LCM of 10 and 7 is 70.
|
Joelle |
Linda |
Total |
Before |
70 u |
50 u |
120 u |
Change |
- 10 u |
+ 10 u |
|
After |
60 u |
60 u |
120 u |
Total number of erasers that Joelle and Linda have
= 70 u + 50 u
= 120 u
After Joelle gives to Linda, both of them will have the same number of erasers.
The total number of erasers that Joelle and Linda have remains unchanged.
Number of erasers that each of them will have
= 120 u ÷ 2
= 60 u
Number of erasers that Joelle gives to Linda
= 70 u - 60 u
= 10 u
10 u = 120
1 u = 120 ÷ 10 = 12
Total number of erasers that three of them have
= 120 u + 21 u
= 141 u
Average number of erasers that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 12
= 564
Answer(s): 564