A container contains some pears, passion fruits and oranges. 0.2 of the pears is equal to 30% of the passion fruits. The number of oranges is ⁴₇ of the total number of passion fruits and pears. If there are 48 more oranges than passion fruits, how many fruits are there in the container altogether?

Pears	Passion Fruits	Oranges
3x7	2x7
7x5		4x5
21 u	14 u	20 u

0.2 = ²₁₀= ¹₅
30% = ³⁰₁₀₀ = ³₁₀

0.2 of the pears is equal to 30% of the passion fruits. Make the numerators the same.  LCM of 1 and 3 is 3.

1x35x3 of the pears = 3x110x1 of the passion fruits
315 of the pears = 310 of the passion fruits 

Pears : Passion Fruits
15 : 10 _(÷5)
3 : 2

The total number of pears and passion fruits is repeated.  Make the total number of pears and passion fruits the same.  LCM of 5 and 7 is 35.

Number of more oranges than passion fruits
= 20 u - 14 u
= 6 u

6 u = 48

1 u = 48 ÷ 6 = 8

Number of the fruits in the container altogether
= 21 u + 14 u + 20 u
= 55 u
= 55 x 8
= 440

Answer(s): 440