A jar contained $2 and $5 notes with a total value of $105. 10 pieces of $5 were exchanged for $2 notes of similar value. In the end, the number of $2 notes was the same as the $5 notes. How many $5 notes were there at first?
| |
$2 |
$5 |
| Before |
1 u - 25 |
1 u + 10 |
| Change |
+ 25 |
- 10 |
| After |
1 u |
1 u |
Total value of $2 and $5 notes remains unchanged after the exchange of notes of similar value.
Total value of 10 pieces of $5-notes
= 10 x 5
= $50
Number of $2-notes that 10 pieces of $5-notes were exchanged for
= 50 ÷ 2
= 25
| In the end |
$2 |
$5 |
Total |
| Number |
1 u |
1 u |
2 u |
| Value |
2 |
5 |
|
| Total Value |
2 u |
5 u |
7 u |
Total value of $2 and $5 notes
= 2 u + 5 u
= 7 u
7 u = 105
1 u = 105 ÷ 7 = 15
Number of $5 notes at first
= 1 u + 10
= 15 + 10
= 25
Answer(s): 25
