Warren had 40% more balls than Xavier. Warren gave 20% of his balls to Xavier. Xavier in return gave 25% of his balls to Warren. In the end, Xavier had 336 less balls than Warren. How many balls did Warren have at first?
| |
Warren |
Xavier |
| Before |
140% |
100% |
| Change 1 |
- 28% |
+ 28% |
| After 1 |
112% |
128% |
| Change 2 |
+ 32% |
- 32% |
| After 2 |
144% |
96% |
Number of balls that Warren had at first in percent
= 100% + 40%
= 140%
Number of balls that Warren gave to Xavier in percent
= 20% x 140%
=
20100 x 140%
= 28%
Number of balls that Xavier gave to Warren in percent
= 25% x 128%
=
25100 x 128%
= 32%
Number of less balls that Xavier had than Warren in the end
= 144% - 96%
= 48%
48% → 336
1% → 336 ÷ 48 = 7
Number of balls that Warren had at first
= 140%
= 140 x 7
= 980
Answer(s): 980
