Level 3
Willi noticed the patterns on the square tiles and tried to calculate the area of the shaded part. Leave the answer in 2 decimal places.
(Take π = 3.14)
Level 3
Willi noticed the patterns on the square tiles and tried to calculate the area of the shaded part. Leave the answer in 2 decimal places.
(Take π = 3.14)
Image in this question is not available.
Level 3
The figure shows a circle with centre O and diameter, 14 cm. ABCD and OAEB are squares. Find the total area of the shaded portions of the figure. (Take π = 227)
Level 3
The figure shows a circle with centre O and diameter, 14 cm. ABCD and OAEB are squares. Find the total area of the shaded portions of the figure. (Take π = 227)
Image in this question is not available.
Level 3
The figure is made up of semicircles, a square, ABDF, and a rectangle, BCEF. The length of the square, ABDF, is 20 cm. Find the area of the shaded figure. Leave the answer in terms of π .
Level 3
The figure is made up of semicircles, a square, ABDF, and a rectangle, BCEF. The length of the square, ABDF, is 20 cm. Find the area of the shaded figure. Leave the answer in terms of π .
Image in this question is not available.
Level 3
Mr Tan owned a rectangular piece of land, ABCD, as shown in the figure. A path of width 3 m was tiled around the pool and the garden. The area of the square pool was 196 m2 and the area of rectangular garden was 308m2. Find the area of the piece of land.
Level 3
Mr Tan owned a rectangular piece of land, ABCD, as shown in the figure. A path of width 3 m was tiled around the pool and the garden. The area of the square pool was 196 m2 and the area of rectangular garden was 308m2. Find the area of the piece of land.
Image in this question is not available.
Level 3
The figure is made up of a rectangle and a square. Find the area of the figure.
Level 3
The figure is made up of a rectangle and a square. Find the area of the figure.
Image in this question is not available.
Level 3
The figure is made up of a quadrant, a square and a semicircle. The area of the square is 144 cm2. Find the area of the shaded parts. (Take π = 3.14)
Level 3
The figure is made up of a quadrant, a square and a semicircle. The area of the square is 144 cm2. Find the area of the shaded parts. (Take π = 3.14)
Image in this question is not available.
Level 3
Find (a) the area and (b) the perimeter of the figure. (Take π = 227)
Level 3
Find (a) the area and (b) the perimeter of the figure. (Take π = 227)
Image in this question is not available.
Level 3
The figure consists of 2 squares of side 12 cm and 6 cm respectively. What is the area of the shaded triangle?
Level 3
The figure consists of 2 squares of side 12 cm and 6 cm respectively. What is the area of the shaded triangle?
Image in this question is not available.
Level 3
Find the:
- area and
- perimeter of the shaded part.
The diameter of the small circle is 6 cm. (Take π = 3.14)
Level 3
Find the:
- area and
- perimeter of the shaded part.
The diameter of the small circle is 6 cm. (Take π = 3.14)
Image in this question is not available.
Level 3
ABFG and CDEF are squares. The area of CDEF is 121 cm2. Find the total shaded area in the figure.
Level 3
ABFG and CDEF are squares. The area of CDEF is 121 cm2. Find the total shaded area in the figure.
Image in this question is not available.
Level 3
The figure is made up of identical quadrants. The radius is 10 cm long. Take π as 3.14.
- Find the area of the shaded part.
- Find the perimeter of the shaded part.
Level 3
The figure is made up of identical quadrants. The radius is 10 cm long. Take π as 3.14.
- Find the area of the shaded part.
- Find the perimeter of the shaded part.
Image in this question is not available.
Level 3
The rectangle is made up of some triangles. The three shaded triangles are identical. The perimeter of the rectangle is 84 cm. Its breath is 15 cm. Find the total area of the shaded triangles.
Level 3
The rectangle is made up of some triangles. The three shaded triangles are identical. The perimeter of the rectangle is 84 cm. Its breath is 15 cm. Find the total area of the shaded triangles.
Image in this question is not available.
Level 3 PSLE
OPQRS is part of a circle of radius 10 cm. OPR and OQS are quarter circles. The area of the shaded part OQR is 40 cm
2 and the perimeter of the shaded part OQR is 30 cm. For each of the following, use the calculator value of π to find:
- the area of the figure OPQRS, correct to 2 decimal places,
- the perimeter of the figure OPQRS, correct to 1 decimal places.
Level 3 PSLE
OPQRS is part of a circle of radius 10 cm. OPR and OQS are quarter circles. The area of the shaded part OQR is 40 cm
2 and the perimeter of the shaded part OQR is 30 cm. For each of the following, use the calculator value of π to find:
- the area of the figure OPQRS, correct to 2 decimal places,
- the perimeter of the figure OPQRS, correct to 1 decimal places.
Image in this question is not available.
Level 3
The shape, not drawn to scale, is made up of a square and some triangles. Find the shaded area.
Level 3
The shape, not drawn to scale, is made up of a square and some triangles. Find the shaded area.
Image in this question is not available.
Level 3
The figure shows one big quadrant and two small semicircles. The radius of the big quadrant is 60 cm.
- Find the perimeter of the shaded figure. (Take π = 3.14)
- Find the shaded area of this figure. (Take π = 3.14)
Level 3
The figure shows one big quadrant and two small semicircles. The radius of the big quadrant is 60 cm.
- Find the perimeter of the shaded figure. (Take π = 3.14)
- Find the shaded area of this figure. (Take π = 3.14)
Image in this question is not available.
Level 3
The figure is not drawn to scale. ABCD is a rectangle. M is the midpoint of AB and N is the midpoint of DC. Given that AE = FD = BG = HC and EF = GH = 4 cm, Find the area of the shaded part.
Level 3
The figure is not drawn to scale. ABCD is a rectangle. M is the midpoint of AB and N is the midpoint of DC. Given that AE = FD = BG = HC and EF = GH = 4 cm, Find the area of the shaded part.
Image in this question is not available.
Level 3
In the figure, WXYZ and XYML are squares. P and N are centres of square WXYZ and PQRS respectively. O is the centre of XY. If WL = 56 cm, take π =
227 and
find
- the perimeter of the shaded region,
- the area of the shaded region.
Level 3
In the figure, WXYZ and XYML are squares. P and N are centres of square WXYZ and PQRS respectively. O is the centre of XY. If WL = 56 cm, take π =
227 and
find
- the perimeter of the shaded region,
- the area of the shaded region.
Image in this question is not available.
Level 3
The figure shows a rectangle of area 108 cm2. Given that DE = EF = FC, find the total area of the shaded parts in the figure.
Level 3
The figure shows a rectangle of area 108 cm2. Given that DE = EF = FC, find the total area of the shaded parts in the figure.
Image in this question is not available.
Level 3
The figure is not drawn to scale. It is formed by quadrants and semicircles of two sizes. The radius of the larger quadrant is 3 cm longer than the radius of the smaller quadrant. The radius of the smaller quadrant (Line B) is 12 cm.
- Find the area of the shaded part.
- Find the perimeter of the dotted line. (Take π = 3.14)
Level 3
The figure is not drawn to scale. It is formed by quadrants and semicircles of two sizes. The radius of the larger quadrant is 3 cm longer than the radius of the smaller quadrant. The radius of the smaller quadrant (Line B) is 12 cm.
- Find the area of the shaded part.
- Find the perimeter of the dotted line. (Take π = 3.14)
Image in this question is not available.
Level 3
The figure shows a rectangular park which consists of 1 pavilion in a semi-circle
shape and a pond. 4 quarter circles make up the shape of the pond. The length and
breadth of the rectangle are 80 m and 44 m respectively.
- Find the perimeter of the pond.
- Find the area of the shaded part. (Take π = 3.14).
Level 3
The figure shows a rectangular park which consists of 1 pavilion in a semi-circle
shape and a pond. 4 quarter circles make up the shape of the pond. The length and
breadth of the rectangle are 80 m and 44 m respectively.
- Find the perimeter of the pond.
- Find the area of the shaded part. (Take π = 3.14).
Image in this question is not available.