Level 3
At 8 a.m., Shaira and Joana raced off together from the starting point of a trail. Shaira ran at an average speed of 3 m/s. Joana ran at an average speed of 4 m/s. Upon reaching the end of the trail, Joana rested for 5 minutes. She then immediately ran back along the same route at 4 m/s. At 8.40 a.m., Shaira met Joana.
Find the total distance covered by the two runners when they met each other. Express the answer in km.
Level 3
The figure shows a square that is cut out from a big triangle. The area of the triangle and that of the square are whole numbers. Both the height and the base of the triangle are equal. If the shaded area is 73 cm2, find
The length of the square
The base of the triangle
Level 3
The figure shows a square that is cut out from a big triangle. The area of the triangle and that of the square are whole numbers. Both the height and the base of the triangle are equal. If the shaded area is 73 cm2, find
Level 3
The figure, not drawn to scale, is made up of 2 identical squares, ABCD and WXYZ. The length of each square is 10 cm. Point W is the centre of square ABCD.
What fraction of the figure is shaded?
What is the area of the unshaded parts?
Level 3
The figure, not drawn to scale, is made up of 2 identical squares, ABCD and WXYZ. The length of each square is 10 cm. Point W is the centre of square ABCD.
Level 3
The figure shows a rectangle WXYZ. The lines are extended from point W, X, Y and Z and they meet at point B. The length of YZ is 30 cm. Given that the area of triangle WBZ is 65 cm2 and the area of triangle XBY is 105 cm2, find the breadth of the rectangle in mixed number.
Level 3
The figure shows a rectangle WXYZ. The lines are extended from point W, X, Y and Z and they meet at point B. The length of YZ is 30 cm. Given that the area of triangle WBZ is 65 cm2 and the area of triangle XBY is 105 cm2, find the breadth of the rectangle in mixed number.
Level 3
In the figure, ABCD is a parallelogram with length AD twice the length of AB. ADE is an equilateral triangle. F is a point on AE such that AF = FE. ∠BCD is 104°. Find ∠FBC .
Level 3
In the figure, ABCD is a parallelogram with length AD twice the length of AB. ADE is an equilateral triangle. F is a point on AE such that AF = FE. ∠BCD is 104°. Find ∠FBC .
