The figure shows a rectangular field EFGH. Mike walked from E to F to G to H and he covered a distance of 57m. Sandy walked from F to G to H to E and she covered a distance of 48m. What is the perimeter of the field?
Some construction work was undertaken to the same field and a semi-circular part was removed from it. What is the perimeter of the field after the construction? (Take π = 227)
Level 3
The figure shows a rectangular field EFGH. Mike walked from E to F to G to H and he covered a distance of 57m. Sandy walked from F to G to H to E and she covered a distance of 48m. What is the perimeter of the field?
Some construction work was undertaken to the same field and a semi-circular part was removed from it. What is the perimeter of the field after the construction? (Take π = 227)
Level 3
Three similar sections are cut away from an equilateral cardboard triangle ABC. Each side of the equilateral triangle is 56 cm. Find the perimeter of the remaining cardboard. (Take π = 3.14)
Level 3
Three similar sections are cut away from an equilateral cardboard triangle ABC. Each side of the equilateral triangle is 56 cm. Find the perimeter of the remaining cardboard. (Take π = 3.14)
Level 3
A piece of rope is used to make the figure shown. Inside the big semicircle are 2 small circles and 3 small semi-circles, all of which have the same radius. The diameter of the big semicircle is 30 cm. Find the area of the shaded region. (Leave the answer in terms of π)
Level 3
A piece of rope is used to make the figure shown. Inside the big semicircle are 2 small circles and 3 small semi-circles, all of which have the same radius. The diameter of the big semicircle is 30 cm. Find the area of the shaded region. (Leave the answer in terms of π)
Level 3
The figure is made up of a big semicircle of diameter 8 cm and 2 small semicircles with diameter 5.7 cm. Find the shaded area. Round off the answer to nearest 1 decimal place. (Take π = 3.14)
Level 3
The figure is made up of a big semicircle of diameter 8 cm and 2 small semicircles with diameter 5.7 cm. Find the shaded area. Round off the answer to nearest 1 decimal place. (Take π = 3.14)