Level 3
In the figure, ABCD is a parallelogram with length AD twice the length of AB. ADE is an equilateral triangle. F is a point on AE such that AF = FE. ∠BCD is 104°. Find ∠FBC .
Level 3
In the figure, ABCD is a parallelogram with length AD twice the length of AB. ADE is an equilateral triangle. F is a point on AE such that AF = FE. ∠BCD is 104°. Find ∠FBC .
Level 3 PSLE
In the figure, XYZ is a triangle. P, R and S are points on the triangle such that XP = XR and SZ = PZ. If ∠XPR = 104°and ∠SPZ = 123°, find ∠RYS.
Level 3 PSLE
In the figure, XYZ is a triangle. P, R and S are points on the triangle such that XP = XR and SZ = PZ. If ∠XPR = 104°and ∠SPZ = 123°, find ∠RYS.
Level 3
In the figure not drawn to scale, O is the centre of the circle and RSU and PST are straight lines. If ∠TSU = 54° and ∠RSO is twice of ∠OSP, find ∠Q.
Level 3
In the figure not drawn to scale, O is the centre of the circle and RSU and PST are straight lines. If ∠TSU = 54° and ∠RSO is twice of ∠OSP, find ∠Q.