41 P6.ST.JC.18121333
Level 3
4 u - 3 = 1 p
7 u - 4 = 2 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
42 P6.ST.JC.18121334
Level 3
2 + 3 u = 1 p
28 - 2 u = 3 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
43 P6.ST.JC.18121335
Level 3
11 - 3 u = 1 p
36 - 8 u = 4 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
44 P6.ST.JC.18121336
Level 3
4 + 1 u = 1 p
20 u - 5 = 3 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
45 P6.ST.JC.18121337
Level 3
7 - 1 u = 1 p
2 u - 2 = 2 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
46 P6.ST.JC.18121338
Level 3
7 - 1 u = 1 p
5 u + 10 = 4 p

Find the following values.
  1. 1 u
  2. 1 p u = 2 p = 5
3 m
W 4 operations Units & parts Substitution
47 P6.ST.JC.18121339
Level 3
2 u + 4 = 2 p
5 u + 20 = 7 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
48 P6.ST.JC.18121340
Level 3
2 u - 4 = 2 p
3 u + 6 = 7 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
49 P6.ST.JC.18121341
Level 3
5 u - 14 = 2 p
1 + 2 u = 3 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
50 P6.ST.JC.18121342
Level 3
5 u - 1 = 7 p
3 u - 16 = 3 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
51 P6.ST.JC.18121343
Level 3
36 + 2 u = 7 p
5 u - 26 = 3 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
52 P6.ST.JC.18121344
Level 3
22 - 3 u = 4 p
2 u + 8 = 3 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
53 P6.ST.JC.18121345
Level 3
28 - 2 u = 4 p
5 u - 5 = 3 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
54 P6.ST.JC.18121346
Level 3
24 - 4 u = 3 p
26 - 2 u = 5 p

Find the following values.
  1. 1 u
  2. 1 p
3 m
W 4 operations Units & parts Substitution
55 P6.FR.JC.22050805
Level 3 PSLE
Mr Wong used 38 of his money to buy 8 apples and 12 peaches. The cost of 4 apples was the same as that of 2 peaches. What was the most number of peaches that Mr Wong could buy with the money he had left?
2 m
F Multiplication Min-max Equal stage Units method Units & parts Substitution
56 P6.AG.JC.15051409
Level 2 PSLE
Jasmine had a piece of ribbon 17p cm long. She formed a triangle, with sides measuring p cm, 5p cm and 30 cm, with part of the wire.
  1. Express the length of the remaining ribbon in terms of p in the simplest form.
  2. Jasmine used the remaining ribbon to form a rectangle of length 3p cm. If p = 8, what was the breadth of the rectangle?
3 m
Algebra in 1 variable Algebra simplifying Algebra substitution Length Area perimeter Rectangle
57 P6.AG.JC.17080464
Level 3
The total mass of Cindy, Jen and Marvin is 15p kg. Cindy has a mass of 5p kg. Jen is 2 kg heavier than Cindy.
  1. What is Marvin's mass in terms of p?
  2. If p = 10, what is Marvin's mass?
3 m
Algebra in 1 variable Algebra Substitution Mass More than or less than
58 P6.AG.JC.17080458
Level 3
The table shows the number of pens sold at a bookshop last week.
  1. What was the total number of pens sold last week? Express your answer in terms of b the simplest form.
  2. If b = 20, how many pens were sold on Sunday?
3 m
Algebra in 1 variable Algebra simplifying Algebra substitution Table
59 P6.AG.JC.17080462
Level 3
Sam saved $9 each day and Joelle saved $c more than Sam each day. After 2 weeks, they were still short of $30 to buy a TV set.
  1. How much did the TV set cost? Express your answer in terms of c.
  2. If c = $2, how much did the TV set cost?
3 m
Algebra in 1 variable Algebra simplifying Algebra substitution Money More than or less than
60 P6.AG.JC.17080465
Level 3
Abel has b coins. Bobby has three times as many coins as Abel but 8 coins fewer than Jason.
  1. How many coins do they have altogether? (Express your answer in terms of b).
  2. If b = 9, how many stamps do the three boys have altogether?
3 m
Algebra in 1 variable Algebra simplifying Algebra substitution More than or less than Times as many

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