Level 3
The figure shows a rectangular park which consists of 1 pavilion in a semi-circle
shape and a pond. 4 quarter circles make up the shape of the pond. The length and
breadth of the rectangle are 80 m and 44 m respectively.
Find the perimeter of the pond.
Find the area of the shaded part. (Take π = 3.14).
Level 3
The figure shows a rectangular park which consists of 1 pavilion in a semi-circle
shape and a pond. 4 quarter circles make up the shape of the pond. The length and
breadth of the rectangle are 80 m and 44 m respectively.
Find the perimeter of the pond.
Find the area of the shaded part. (Take π = 3.14).
Level 3 PSLE The figure is made up of 6 identical quadrants and 2 identical semicircles. The radius of each quadrant is 14 cm.
The unshaded area marked A is enclosed by 2 quadrants and 2 semicircles. (Take π = 3.14)
Find the perimeter of A.
Find the total shaded areas.
Level 3 PSLE The figure is made up of 6 identical quadrants and 2 identical semicircles. The radius of each quadrant is 14 cm.
The unshaded area marked A is enclosed by 2 quadrants and 2 semicircles. (Take π = 3.14)
Level 3 PSLE Tom designed a logo as shown. The logo is made up of 2 small identical quarter circles, a large quarter circle and 2 straight lines drawn inside a square of side 42 cm. The radius of each small quarter circle is 14 cm.
What is the perimeter of the shaded part?
What is the area of the shaded part?
Level 3 PSLE Tom designed a logo as shown. The logo is made up of 2 small identical quarter circles, a large quarter circle and 2 straight lines drawn inside a square of side 42 cm. The radius of each small quarter circle is 14 cm.
Level 3 PSLE
The figure is made up of three rectangles. A straight line drawn across the rectangles, divides the figure into two parts: shaded and unshaded.
The perimeter of the shaed part is 8 cm longer than the perimeter of the unshaded part. What is the length of AB?
What is the area of the shaded part?
Level 3 PSLE
The figure is made up of three rectangles. A straight line drawn across the rectangles, divides the figure into two parts: shaded and unshaded.
The perimeter of the shaed part is 8 cm longer than the perimeter of the unshaded part. What is the length of AB?
Level 3 The figure shows a rectangle with its corners cut out. Each of the 4 identical corners cut out is a quarter circle. The ratio of the length of the rectangle to its breadth is 13 : 5.
What is the radius of each quarter circle?
What is the perimeter of the shaded part. Take π = 3.14. Give your answer correct to 1 decimal place.
Level 3 The figure shows a rectangle with its corners cut out. Each of the 4 identical corners cut out is a quarter circle. The ratio of the length of the rectangle to its breadth is 13 : 5.
What is the radius of each quarter circle?
What is the perimeter of the shaded part. Take π = 3.14. Give your answer correct to 1 decimal place.
Level 2 PSLE A symmetric figure is drawn on a rectangular piece of paper 20 cm by 15 cm as shown. Its outline consists of a large semicircle, 2 smaller semicircles and 2 straight lines.
What is the area of the figure?
What is its perimeter? Take π = 3.14
Level 2 PSLE A symmetric figure is drawn on a rectangular piece of paper 20 cm by 15 cm as shown. Its outline consists of a large semicircle, 2 smaller semicircles and 2 straight lines.
Level 3 PSLE
A small circle with centre O has been cut from a circular piece of cardboard with the same centre. The radius of the small circle is 8 cm.
The remaining cardboard is then cut into four equal parts along the dotted lines as shown in Figure 1. The four parts are rearranged to form a new shape in Figure 2.
Find the area of the new shape.
Find the perimeter of the new shape. (Take π = 3.14)
Level 3 PSLE
A small circle with centre O has been cut from a circular piece of cardboard with the same centre. The radius of the small circle is 8 cm.
The remaining cardboard is then cut into four equal parts along the dotted lines as shown in Figure 1. The four parts are rearranged to form a new shape in Figure 2.
Find the area of the new shape.
Find the perimeter of the new shape. (Take π = 3.14)