1 P5.RD.JC.17083139
Level 2
The figure consists of 2 squares X and Y overlapping each other. The ratio of the area of Square X to the area of Square Y is 3 : 8. Given that 14 of Y is shaded, what is the ratio of the shaded part to the area of the figure?
2 m
Fraction of a whole Fraction to units Finding ratio Area perimeter Overlapping area Square Repeated identity Units method
2 P5.RD.JC.17083143
Level 2
The figure is made up of 2 triangles, A and B, overlapping each other. 1011 of A is shaded and 45 of B is shaded. What is the ratio of the shaded area of A to the figure?
2 m
Finding ratio R Simplest form Fraction to units Area perimeter Triangle Overlapping area Repeated identity Units table
3 P5.RD.JC.17083106
Level 2
The figure is not drawn to scale. It shows 2 identical squares. 14 of a square overlaps with the other. What is the ratio of the overlapping area to the total area of the figure?
2 m
Fraction to units Finding ratio Area Perimeter Square Overlapping area Square Repeated identity Units method
4 P5.RD.JC.17083018
Level 2
The figure consists of 2 squares A and B whose areas are in the ratio of 3 : 1. Given that 112 of Square A is shaded, what fraction of Square B is shaded?
2 m
Fraction of a whole Fraction to units Ratio to units Area perimeter Square Overlapping area Repeated identity Remainder concept Units table
5 P5.RA.JM.17083117
Level 2
Manny designed a logo using three ovals. The areas of the ovals were in the ratio of 1 : 4 : 13. He then shaded some parts of the logo as shown. What was the ratio of the shaded area to the unshaded area of the logo?
2 m
Finding ratio Ratio to units Overlapping area Units method
6 P6.FR.JC.17050718
Level 2
The figure is made up of a rectangle and a square. 79 of the square is unshaded and 16 of the rectangle is shaded. What fraction of the figure is shaded?
2 m
Fraction of a whole Fraction to units Area perimeter Square Rectangle Overlapping area Repeated identity Units table
7 P6.RD.JC.16010108
Level 3
This figure is not drawn to scale. It is made up of 3 squares. The ratio of the area of the smallest square to the largest square is 2 : 9 while the shaded area is 37 of the unshaded area. What is the ratio of the shaded area to the area of the smallest square?
3 m
Fraction of a whole Ratio to units Area perimeter Square Overlapping area Unchanged total Units table
8 P5.RD.PR.17083249
Level 3
The figure is made up of 2 squares of different sizes. The area of the small square is 50% of the area of the big square. The overlapped shaded area is 20 cm2. The area of the unshaded small square is 25 the area of the unshaded big square. Find the area of the small square.
3 m
Fraction to units Finding ratio Area Perimeter Square Overlapping area Unchanged difference Units table
9 P6.RA.TL.16010110
Level 3
The figure is not drawn to scale. It is made up of a square and a rectangle. The ratio of the area of the square to that of the rectangle is 3 : 4. After the shaded part is cut out, the ratio of the area of unshaded part of the rectangle to that of the unshaded part of the square is 2 : 1. Given the length of the square is 9 cm, find the area of the shaded part.
3 m
Ratio to units Area perimeter Square Rectangle Overlapping area Unchanged difference Units table
10 P6.RA.TL.17042601
Level 3
The figure, not drawn to scale, shows 2 rectangles overlapping each other. The ratio of the shaded area to the area of Rectangle A is 3 : 8. The ratio of the shaded area to the area of Rectangle B is 2 : 5. Find the ratio of the unshaded area to the total area of the figure.
3 m
Finding ratio LCM Overlapping area Unchanged difference Units method
11 P6.RA.TL.17042602
Level 3
The figure, not drawn to scale, on the right shows 2 rectangles overlapping each other. The ratio of the shaded area to the area of Rectangle X is 4 : 9. The ratio of the shaded area to the area of Rectangle Y is 3 : 6. Find the ratio of the unshaded area to the total area of the figure.
3 m
Finding ratio LCM Area perimeter Rectangle Overlapping area Unchanged difference Units method
12 P5.AP.JM.17083242
Level 2
The figure shown is cut from a piece of paper. ABCD is a square and EFGH is a rectangle. Find the area of the figure.
2 m
Square Rectangle Composite figure area Overlapping area
13 P6.AP.NK.21060430
Level 3 PSLE
Two rectangular mats, each 6 m by 4 m, are place on the floor of a rectangular room as shown. The mats overlap. The area of the floor covered by the overlap is 5.6 cm2. Find the area of the floor not covered by the mats.
2 m
Rectangle Overlapping area
14 P6.AP.NK.21060431
Level 3 PSLE
Figure ABCDE has an area of 42 cm2. ABD and CBE are straight lines. Find the area of the shaded triangle BDE.
2 m
Triangle Composite figure area Overlapping area
15 P6.AP.NK.21060432
Level 3 PSLE
In the figure, ABC and XZY are identical right-angled triangles. The total area of the shaded parts is 96 cm2. Find the area of the unshaded part.
2 m
Right-angled triangle Composite figure area Overlapping area
16 P6.AP.JC.22050403
Level 3
In the figure, ABC and ADE are right-angled isosceles triangles. BD = CE = 2 cm. The shaded area is 22 cm2. Find the length of AC.
2 m
Length Isosceles triangle Right-angled triangle Overlapping area
17 P5.AP.NK.23041223
Level 2
The figure is made up of three triangles, ABC, XYZ and DEF not drawn to scale. The area of triangle XYZ is six times the area of triangle ABC. The area of triangle ABC is 13 of triangle DEF. The area of triangle ABC is 12 cm2. What is the total area of the shaded parts?
2 m
Triangle Composite figure area Overlapping area Fraction to units Repeated identity Units method
18 P6.AP.TL.17090785
Level 3
Two identical right-angled triangles overlap each other as shown. Find the area of the shaded part.
2 m
Rectangle Right-angled triangle Overlapping area
19 P6.AP.TL.17090759
Level 2 PSLE
The shaded figure is formed by two identical circles with centres at A and C. ABCD is a square and the length of AB is 7 cm. Find the perimeter of the shaded figure. (Take π = 227)
2 m
Square Circle Circumference Composite figure perimeter Overlapping area
20 P6.AP.TL.17090758
Level 2
X, Y and Z are centres of three identical circles. The length of XY is 7.2 m. XY, YZ and XZ are equal in length. Find the shaded area of the figure. (Take π = 3.14) Correct to 2 decimal places.
2 m
Triangle Circle Composite figure area Overlapping area D Place values D Round off

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